2[n-4(4n+22)+10]=2(n+12)

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Solution for 2[n-4(4n+22)+10]=2(n+12) equation:


Simplifying
2[n + -4(4n + 22) + 10] = 2(n + 12)

Reorder the terms:
2[n + -4(22 + 4n) + 10] = 2(n + 12)
2[n + (22 * -4 + 4n * -4) + 10] = 2(n + 12)
2[n + (-88 + -16n) + 10] = 2(n + 12)

Reorder the terms:
2[-88 + 10 + n + -16n] = 2(n + 12)

Combine like terms: -88 + 10 = -78
2[-78 + n + -16n] = 2(n + 12)

Combine like terms: n + -16n = -15n
2[-78 + -15n] = 2(n + 12)
[-78 * 2 + -15n * 2] = 2(n + 12)
[-156 + -30n] = 2(n + 12)

Reorder the terms:
-156 + -30n = 2(12 + n)
-156 + -30n = (12 * 2 + n * 2)
-156 + -30n = (24 + 2n)

Solving
-156 + -30n = 24 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
-156 + -30n + -2n = 24 + 2n + -2n

Combine like terms: -30n + -2n = -32n
-156 + -32n = 24 + 2n + -2n

Combine like terms: 2n + -2n = 0
-156 + -32n = 24 + 0
-156 + -32n = 24

Add '156' to each side of the equation.
-156 + 156 + -32n = 24 + 156

Combine like terms: -156 + 156 = 0
0 + -32n = 24 + 156
-32n = 24 + 156

Combine like terms: 24 + 156 = 180
-32n = 180

Divide each side by '-32'.
n = -5.625

Simplifying
n = -5.625

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